In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr. The mass percentage of bromine in the compound is .

(Atomic mass: Ag = 108, Br = 80 )

Question

In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr. The mass percentage of bromine in the compound is .

(Atomic mass: Ag = 108, Br = 80 )

Canvas Classes · Accepted Answer

Step 1: Recall Carius Method Formula for Bromine

Where molar mass of  = 108 + 80 = 188 g/mol

Step 2: Substitute Given Values

-  = 1.88 g
-  = 1.6 g

Step 3: Calculate Percentage of Bromine

Answer: 50%

Elegant shortcut:

Notice that , which means the ratio exactly cancels to give a clean answer of 50%.

Key Points to Remember:
- When  g and compound = 1.6 g, notice  — the 188 (MW of AgBr) cancels perfectly → clean 50%
- %Br = 50% means one Br per ~160 Da of compound (MW ≈ 160, e.g.,

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