20 mL of 0.1 M NaOH is added to 50 mL of 0.1 M acetic acid solution. The pH of the resulting solution is . (Nearest integer)

Question

Canvas Classes · Accepted Answer

Step 1 — Moles of each:
Moles NaOH =  mol
Moles  =  mol

Step 2 — After neutralisation:
 remaining =  mol
 formed =  mol

Step 3 — Henderson-Hasselbalch:

Expressed as :

Answer: 458

More questions from Ionic Equilibrium