In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is %.

(Molar mass: O = 16, S = 32, Ba = 137 in )

Question

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is   %.

(Molar mass: O = 16, S = 32, Ba = 137 in )

Canvas Classes · Accepted Answer

Step 1: Recall the Carius Method for Sulphur Estimation

In sulphur estimation (Carius method), the organic compound is heated with fuming . Sulphur is oxidised to sulphate and precipitated as barium sulphate:

Step 2: Determine Molar Masses

- Molar mass of  = 137 + 32 + 4(16) = 233 g/mol
- Atomic mass of S = 32 g/mol

Step 3: Calculate Mass of Sulphur

Step 4: Calculate Percentage of Sulphur

Mass of compound = 0.20 g

The question asks for the answer as :

Answer: 275 (nearest integer)

More questions from Practical Organic Chemistry