The molarity of the solution prepared by dissolving 6.3 g of oxalic acid () in 250 mL of water in mol L⁻¹ is . The value of x is . (Nearest integer)

[Atomic mass: H: 1.0, C: 12.0, O: 16.0]

Question

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid () in 250 mL of water in mol L⁻¹ is . The value of x is . (Nearest integer)

[Atomic mass: H: 1.0, C: 12.0, O: 16.0]

Canvas Classes · Accepted Answer

Strategy:
 Molarity () is moles of solute per liter of solution. For oxalic acid dihydrate, the water of crystallization must be included when calculating the molar mass.

Step 1: Calculate the molar mass of oxalic acid dihydrate ()
- 
- 
Molar mass =

Step 2: Calculate the number of moles
Mass = 6.3 g.

Step 3: Find Molarity ()
Volume = 250 mL = 0.25 L.

Step 4: Express as 
.

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