Solution of 12 g of non-electrolyte (A) prepared by dissolving it in 1000 mL of water exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The empirical formula

Question

Solution of 12 g of non-electrolyte (A) prepared by dissolving it in 1000 mL of water exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The empirical formula of A is . The molecular mass of A is  g. (Nearest integer)

Canvas Classes · Accepted Answer

Strategy:
 Isotonic solutions at the same temperature have identical molar concentrations (). Use the molarity of the glucose solution to find the moles of solute A in its solution, and then solve for the molecular mass.

Step 1: Identify that } CA = C{	ext{glucose}}
Glucose concentration = 0.05 M. Thus, Solution A must also be 0.05 M.

Step 2: Calculate the molecular mass () of A
We have 12 g of A in 1000 mL.

Step 3: Confirm with empirical formula
Empirical formula  has a mass of .

Molecu

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