The covalency and oxidation state respectively of boron in , are:

Question

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Strategy:
 Differentiate between covalency (number of bonds formed) and oxidation state.

Step 1: Determine covalency
In the  ion, Boron is bonded to four fluorine atoms (three covalent bonds and one coordinate covalent bond).
Therefore, its covalency is 4.

Step 2: Determine oxidation state
Let  be the oxidation state of Boron.
.
Oxidation state is 3.

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