An alkene "A" on reaction with and gives propanone and ethanal in equimolar ratio. Addition of to alkene "A" gives "B" as the major product. The structure of product "B" is:

Question

An alkene "A" on reaction with  and  gives propanone and ethanal in equimolar ratio. Addition of  to alkene "A" gives "B" as the major product. The structure of product "B" is:

Canvas Classes · Accepted Answer

🧠 The "Aha!" Moment
This is a two-step puzzle. 
Step 1: Use the "scars" of Ozonolysis to reconstruct the original alkene.
Step 2: Add  using Markovnikov's rule to find the final product.

🗺️ The Structural Journey
1. Ozonolysis Reconstruction: 
   - Propanone is .
   - Ethanal is .
   - "Glue" the  carbons together:  (2-Methylbut-2-ene). This is Alkene A.
2. Hydrochlorination: 
   - Add  to .
   - According to Markovnikov's Rule, the Hydrogen adds to the carbon with more hydrogens (the  carbon

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