Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at −24°C is kg

(Molar mass in g mol⁻¹ for ethylene glycol 62, of water = 1.86 K kg mol⁻¹)

Question

Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at −24°C is  kg

(Molar mass in g mol⁻¹ for ethylene glycol 62,  of water = 1.86 K kg mol⁻¹)

Canvas Classes · Accepted Answer

Strategy:
 Freezing point depression () is a colligative property given by . First, find the required molality (), then the total moles of ethylene glycol, and finally the mass in kg.

Step 1: Calculate the required depression in freezing point ()

Step 2: Determine the required molality ()
Given .

Step 3: Calculate the moles of ethylene glycol needed
Mass of solvent (water) = 18.6 kg.

Step 4: Calculate the total mass of ethylene glycol
Molar mass = 62 g/mol.

Rounding to the nearest integ

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