For the reaction $M^{n+} + ne^- \to M(s)$, how d... - Class 12 Chemistry | Canvas Classes | Canvas Classes

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Nernst EquationElectrochemistry

For the reaction $M^{n+} + ne^- \to M(s)$ , how does the electrode potential ( $E$ ) change if the concentration of metal ions is increased?.

Expert Answer

The electrode potential increases (becomes more positive), as per $E = E^\circ - \frac{RT}{nF} \ln \frac{1}{[M^{n+}]}$ .

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