In the electrolysis of aqueous $$H_2SO_4$$, what product is formed at the anode at high current density? (Contrast this with the product at low current density)

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Peroxodisulphate ($$S_2O_8^{2-}$$), instead of $$O_2$$. At low current density (dilute acid), Water is oxidized to give $$O_2$$ gas, $$2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^-$$. JEE Pro-Tip: This reaction is the first step in the industrial manufacture of $$H_2O_2$$(Hydrogen Peroxide). The$$S_2O_8^{2-}$$is hydrolyzed to give$$H_2O_2$$

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