Questions/JEE Main 2026/Quick Calc: $$14 \t...
21 Jan - MorningJEE Main 2026

Quick Calc: 14 g14 \text{ g} Calcium reacts with excess HClHCl . Calculate moles of H2H_2 evolved. ( Ca=40Ca = 40 )

Expert Answer

CaCa is the limiting reagent here. 0.35 mol0.35 \text{ mol} Ca+2HClCaCl2+H2Ca + 2HCl \rightarrow CaCl_2 + H_2 n(Ca)=14/40=0.35n(Ca) = 14/40 = 0.35 . Ratio is 1:1.

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