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21 Jan - MorningJEE Main 2026

Why is [PtCl4]2−[PtCl_4]^{2-} Square Planar while[NiCl4]2−[NiCl_4]^{2-} is Tetrahedral?<br>(Bothd8 d^8+ weak ligand)

Expert Answer

Pt is a 5d metal. For 4d/5d metals, splitting energy is high. Ligands force pairing→dsp2\rightarrow dsp^2.

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