JEE Main · 2019 · Shift-ImediumBOND-122

Among the following, the molecule expected to be stabilized by anion formation is: C2, O2, NO, F2

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Among the following, the molecule expected to be stabilized by anion formation is: C2\mathrm{C_2}, O2\mathrm{O_2}, NO, F2\mathrm{F_2}

Options
  1. a

    F2\mathrm{F_2}

  2. b

    C2\mathrm{C_2}

  3. c

    O2\mathrm{O_2}

  4. d

    NO

Correct Answerb

C2\mathrm{C_2}

Detailed Solution

🧠 A molecule is stabilized by anion formation when adding one electron increases its bond order.

🗺️ Check bond order before and after adding e⁻:

| Molecule | e⁻ | BO | After anion | New BO | Change | |----------|----|----|-------------|--------|--------| | C2\mathrm{C_2} | 12 | 2 | C2\mathrm{C_2^-} (13e) | 2.5 | ↑ ✓ | | O2\mathrm{O_2} | 16 | 2 | O2\mathrm{O_2^-} (17e) | 1.5 | ↓ ✗ | | NO | 15 | 2.5 | NO\mathrm{NO^-} (16e) | 2 | ↓ ✗ | | F2\mathrm{F_2} | 18 | 1 | F2\mathrm{F_2^-} (19e) | 0.5 | ↓ ✗ |

⚡ For C2\mathrm{C_2} , the 13th electron enters a bonding σ2p\sigma_{2p} orbital (since all π and σ below it are filled for N₂-type ordering), raising the bond order.

Answer: C2\boxed{\text{Answer: } \mathrm{C_2}}

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