JEE Main · 2024 · Shift-ImediumBOND-034

Arrange the bonds in order of increasing ionic character in the molecules: LiF, K2O, N2, SO2 and ClF3

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Arrange the bonds in order of increasing ionic character in the molecules: LiF,K2O,N2,SO2\mathrm{LiF, K_2O, N_2, SO_2} and ClF3\mathrm{ClF_3}

Options
  1. a

    ClF3<N2<SO2<K2O<LiF\mathrm{ClF_3 < N_2 < SO_2 < K_2O < LiF}

  2. b

    LiF<K2O<ClF3<SO2<N2\mathrm{LiF < K_2O < ClF_3 < SO_2 < N_2}

  3. c

    N2<SO2<ClF3<K2O<LiF\mathrm{N_2 < SO_2 < ClF_3 < K_2O < LiF}

  4. d

    N2<ClF3<SO2<K2O<LiF\mathrm{N_2 < ClF_3 < SO_2 < K_2O < LiF}

Correct Answerc

N2<SO2<ClF3<K2O<LiF\mathrm{N_2 < SO_2 < ClF_3 < K_2O < LiF}

Detailed Solution

🧠 Ionic character increases with electronegativity difference between bonded atoms. Rank by increasing Δχ (electronegativity difference).

| Bond | Atoms | Δχ | Ionic character | |---|---|---|---| | \ceN2\ce{N2} | N–N | 0 | 0 (purely covalent) | | \ceSO2\ce{SO2} | S–O | small | low | | \ceClF3\ce{ClF3} | Cl–F | moderate | moderate | | \ceK2O\ce{K2O} | K–O | large | high ionic | | LiF | Li–F | largest | highest ionic |

⚡ N–N bond is the anchor: identical atoms → Δχ = 0 → purely covalent → least ionic. Li–F has the greatest Δχ among common bonds.

Answer: (c) \ceN2<SO2<ClF3<K2O<LiF\boxed{\text{Answer: (c) } \ce{N2 < SO2 < ClF3 < K2O < LiF}}

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