JEE Main · 2022 · Shift-ImediumBOND-035

Arrange the following in the decreasing order of covalent character: (A) LiCl (B) NaCl (C) KCl (D) CsCl

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Arrange the following in the decreasing order of covalent character:

(A) LiCl (B) NaCl (C) KCl (D) CsCl

Options
  1. a

    (A) > (C) > (B) > (D)

  2. b

    (B) > (A) > (C) > (D)

  3. c

    (A) > (B) > (C) > (D)

  4. d

    (A) > (B) > (D) > (C)

Correct Answerc

(A) > (B) > (C) > (D)

Detailed Solution

🧠 Covalent character increases with smaller cation size (Fajan's rules: higher charge density → more polarisation of anion → more covalent). All four are alkali metal chlorides with M⁺ charge.

Ionic radii: \ceLi+\ce{Li+}(76 pm) < \ceNa+\ce{Na+}(102 pm) < \ceK+\ce{K+}(138 pm) < \ceCs+\ce{Cs+}(167 pm)

Smaller rr → greater charge density → greater polarising power → more covalent character.

\ceLiCl>NaCl>KCl>CsCl\ce{LiCl > NaCl > KCl > CsCl} in decreasing covalent character.

⚠️ Trap: Option (d) has D (CsCl) before C (KCl), but \ceCs+\ce{Cs+} is largest → least polarising → least covalent → it should come last.

Answer: (c) A > B > C > D (LiCl > NaCl > KCl > CsCl)\boxed{\text{Answer: (c) A > B > C > D (LiCl > NaCl > KCl > CsCl)}}

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