JEE Main · 2022 · Shift-IeasyBOND-004

Number of electron deficient molecules among the following PH3,\ B2H6,\ CCl4,\ NH3, LiH and BCl3 is

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Number of electron deficient molecules among the following PH3, B2H6, CCl4, NH3\mathrm{PH_3,\ B_2H_6,\ CCl_4,\ NH_3}, LiH and BCl3\mathrm{BCl_3} is

Options
  1. a

    0

  2. b

    1

  3. c

    2

  4. d

    3

Correct Answerc

2

Detailed Solution

🧠 Electron-deficient molecules have a central atom with fewer than 8 electrons after normal covalent bonding. Group 13 elements (B, Al) with 3 bonds and no lone pair are the classic case.

  • \cePH3\ce{PH3}: P has 3 bonds + 1 LP = 8e → satisfied ✗
  • \ceB2H6\ce{B2H6}: Each B has only 3 two-electron bonds (6e around B) in the conventional Lewis sense. Even with 3c–2e bridging bonds, B starts electron-deficient. ✓
  • \ceCCl4\ce{CCl4}: C has 4 bonds = 8e → satisfied ✗
  • \ceNH3\ce{NH3}: N has 3 bonds + 1 LP = 8e → satisfied ✗
  • LiH: ionic compound; not classified as a covalent electron-deficient molecule ✗
  • \ceBCl3\ce{BCl3}: B has 3 bonds = 6e → electron-deficient ✓

⚠️ Trap: LiH is ionic, not covalently electron-deficient. \cePH3\ce{PH3} satisfies the octet with its lone pair — do not confuse lone pair with electron deficiency.

Answer: (c) 2\boxed{\text{Answer: (c) 2}}

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