JEE Main · 2021 · Shift-IIeasyBOND-110

Number of paramagnetic oxides among the following is ____ {Li_2O,\ CaO,\ Na_2O_2,\ KO_2,\ MgO,\ K_2O}

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Number of paramagnetic oxides among the following is ____

Li2O, CaO, Na2O2, KO2, MgO, K2O\mathrm{Li_2O,\ CaO,\ Na_2O_2,\ KO_2,\ MgO,\ K_2O}

Options
  1. a

    1

  2. b

    3

  3. c

    0

  4. d

    2

Correct Answera

1

Detailed Solution

🧠 Paramagnetic = has unpaired electrons. Check each oxide's structure.

| Compound | Anion present | Unpaired e? | |---|---|---| | \ceLi2O\ce{Li2O} | \ceO2\ce{O^{2-}} (oxide) — fully paired | ✗ | | CaO | \ceO2\ce{O^{2-}} — fully paired | ✗ | | \ceNa2O2\ce{Na2O2} | \ceO22\ce{O2^{2-}} (peroxide) — BO=1, all paired | ✗ | | \ceKO2\ce{KO2} | \ceO2\ce{O2-} (superoxide) — 1 unpaired in π\pi^* | ✓ | | MgO | \ceO2\ce{O^{2-}} — fully paired | ✗ | | \ceK2O\ce{K2O} | \ceO2\ce{O^{2-}} — fully paired | ✗ |

Only \ceKO2\ce{KO2} contains the superoxide ion (\ceO2\ce{O2-}) which has 17 electrons and 1 unpaired electron.

Answer: (a) 1\boxed{\text{Answer: (a) 1}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Chemical Bonding) inside The Crucible, our adaptive practice platform.