JEE Main · 2024 · Shift-IeasyCEQ-015

For the given hypothetical reactions, the equilibrium constants are: X Y;\ K1 = 1.0 Y Z;\ K2 = 2.0 Z W;\ K3 = 4.0 The…

Chemical Equilibrium · Class 11 · JEE Main Previous Year Question

Question

For the given hypothetical reactions, the equilibrium constants are: $\mathrm{X \rightleftharpoons Y};\ K_1 = 1.0 \quad \mathrm{Y \rightleftharpoons Z};\ K_2 = 2.0 \quad \mathrm{Z \rightleftharpoons W};\ K_3 = 4.0$ The equilibrium constant for the reaction $\mathrm{X \rightleftharpoons W}$ is

Options

a
6.0
b
12.0
c
7.0
d
8.0
✓

Correct Answerd

8.0

Detailed Solution

Rule: When reactions are added, their equilibrium constants are multiplied.

Step 1 — Add all three reactions: $\mathrm{X \rightleftharpoons Y} \quad K_1 = 1.0 \mathrm{Y \rightleftharpoons Z} \quad K_2 = 2.0 \mathrm{Z \rightleftharpoons W} \quad K_3 = 4.0$

Net: $\mathrm{X \rightleftharpoons W}$

Step 2 — Combined K: $K = K_1 \times K_2 \times K_3 = 1.0 \times 2.0 \times 4.0 = 8.0$

Answer: Option (4) — 8.0

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