JEE Main · 2022 · Shift-IImediumCK-046

At 30°C, the half life for the decomposition of AB2 is 200 s and is independent of the initial concentration of AB2.…

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

At 30°C30°\mathrm{C}, the half life for the decomposition of AB2\mathrm{AB_2} is 200 s and is independent of the initial concentration of AB2\mathrm{AB_2}. The time required for 80% of the AB2\mathrm{AB_2} to decompose is (Given: log2=0.30\log 2 = 0.30; log3=0.48\log 3 = 0.48)

Options
  1. a

    200 s

  2. b

    323 s

  3. c

    467 s

  4. d

    532 s

Correct Answerc

467 s

Detailed Solution

Half life is independent of initial concentration → first order reaction.

t1/2=200st_{1/2} = 200\,\mathrm{s}, so k=ln2200=0.693200s1k = \frac{\ln 2}{200} = \frac{0.693}{200}\,\mathrm{s^{-1}}

For 80% decomposition, 20% remains: t=2.303klog10020=2.303×2000.693log5t = \frac{2.303}{k}\log\frac{100}{20} = \frac{2.303 \times 200}{0.693}\log 5

log5=log102=10.30=0.70\log 5 = \log\frac{10}{2} = 1 - 0.30 = 0.70

t=2.303×2000.693×0.70=2.303×200×0.700.693=322.420.693=465.3467st = \frac{2.303 \times 200}{0.693} \times 0.70 = \frac{2.303 \times 200 \times 0.70}{0.693} = \frac{322.42}{0.693} = 465.3 \approx 467\,\mathrm{s}

Answer: Option (3) — 467 s

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