JEE Main · 2019 · Shift-IhardCK-033

Consider the given plots for a reaction obeying Arrhenius equation (0°C < T < 300°C): (K and Ea are rate constant and…

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

Consider the given plots for a reaction obeying Arrhenius equation (0°C<T<300°C0°\mathrm{C} < T < 300°\mathrm{C}): (KK and EaE_a are rate constant and activation energy, respectively) image

Options
  1. a

    I is wrong but II is right

  2. b

    Both I and II are wrong

  3. c

    I is right but II is wrong

  4. d

    Both I and II are correct

Correct Answerd

Both I and II are correct

Detailed Solution

Arrhenius equation: k=AeEa/RTk = Ae^{-E_a/RT}, so lnk=lnAEaRT\ln k = \ln A - \frac{E_a}{RT}

Plot Ilnk\ln k vs TT: As TT increases, lnk\ln k increases (non-linearly, since the relationship is lnk1/T\ln k \propto -1/T). The curve is concave and increasing. Correct.

Plot IIlnk\ln k vs 1/T1/T: This gives a straight line with slope =Ea/R= -E_a/R (negative slope). Correct.

Answer: Option (4) — Both I and II are correct

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Consider the given plots for a reaction obeying Arrhenius equation (0°C < T < 300°C): (K and Ea are… (JEE Main 2019) | Canvas Classes