JEE Main · 2019 · Shift-IhardCK-047

For the reaction 2A + B C, the values of initial rate at different reactant concentrations are given in the table…

Chemical Kinetics · Class 12 · JEE Main Previous Year Question

Question

For the reaction 2A+BC\mathrm{2A + B \rightarrow C}, the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reaction is:

| [A](molL1)[\mathrm{A}]\,(\mathrm{mol\,L^{-1}}) | [B](molL1)[\mathrm{B}]\,(\mathrm{mol\,L^{-1}}) | Initial Rate (molL1s1)\,(\mathrm{mol\,L^{-1}\,s^{-1}}) | |:---:|:---:|:---:| | 0.05 | 0.05 | 0.045 | | 0.10 | 0.05 | 0.090 | | 0.20 | 0.10 | 0.72 |

Options
  1. a

    Rate=k[A]2[B]\text{Rate} = k[\mathrm{A}]^2[\mathrm{B}]

  2. b

    Rate=k[A]2[B]2\text{Rate} = k[\mathrm{A}]^2[\mathrm{B}]^2

  3. c

    Rate=k[A][B]\text{Rate} = k[\mathrm{A}][\mathrm{B}]

  4. d

    Rate=k[A][B]2\text{Rate} = k[\mathrm{A}][\mathrm{B}]^2

Correct Answerd

Rate=k[A][B]2\text{Rate} = k[\mathrm{A}][\mathrm{B}]^2

Detailed Solution

Rate law: Rate=k[A][B]2\text{Rate} = k[\mathrm{A}][\mathrm{B}]^2

Answer: Option (4)

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