Mn₂(CO)₁₀ is an organometallic compound due to the presence of:
Coordination Compounds · Class 12 · JEE Main Previous Year Question
Mn₂(CO)₁₀ is an organometallic compound due to the presence of:
- a
Mn–O bond
- b
Mn–Mn bond
- c
C–O bond
- d✓
Mn–C bond
Mn–C bond
🧠 Definition of Organometallic
An organometallic compound is one containing at least one direct metal–carbon (M–C) bond. The M–C bond is the defining feature — not M–O, M–H, or M–M.
🗺️ Evaluate Bonds in Mn₂(CO)₁₀
| Bond present | M–C? | |---|---| | Mn–C (10 terminal CO) | ✓ | | Mn–Mn | metal–metal, not M–C | | C–O (within CO) | not M–C | | Mn–O | not present (CO bonds via C, not O, in terminal carbonyls) |
So qualifies as organometallic because of its Mn–C bonds.
⚡ Carbonyl Coordination Mode
Terminal CO bonds through carbon (the σ-lone pair on C is the donor). The M–C bond is what makes carbonyls organometallic by IUPAC definition.
⚠️ Carbonyls vs Cyanides
Both CN⁻ and CO bond through C, so both metal-cyanides and metal-carbonyls are technically organometallic. Some older definitions exclude , but IUPAC (and JEE NCERT) accept it.
Practice this question with progress tracking
Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Coordination Compounds) inside The Crucible, our adaptive practice platform.
More JEE Main Coordination Compounds PYQs
In which one of the following metal carbonyls, CO forms a bridge between metal atoms?
The coordination geometry around the manganese in decacarbonyldimanganese(0) is:
Given below are two statements: Assertion A: In the complex Ni(CO)₄ and Fe(CO)₅, the metals have zero oxidation state. Reason R: Low oxidation states are found when a complex has ligands capable of…
Low oxidation state of metals in their complexes are common when ligands:
The theory that can completely/properly explain the nature of bonding in [Ni(CO)4] is: