JEE Main · 2021 · Shift-IIeasyDNF-019

The common positive oxidation states for an element with atomic number 24 are:

d & f-Block Elements · Class 12 · JEE Main Previous Year Question

Question

Options

a
+2 to +6
b
+1 and +3 to +6
✓
c
+1 and +3
d
+1 to +6

Correct Answerb

+1 and +3 to +6

Detailed Solution

Z = 24 → Chromium (Cr)

Ground state: $[\text{Ar}]\, 3d^5\, 4s^1$ (special half-filled stability)

Common oxidation states of Cr:

| O.S. | Example | |------|---------| | +1 | $[\text{Cr}(\text{CO})_5\text{Cl}]$ | | +3 | $\text{Cr}_2\text{O}_3$ , $\text{CrCl}_3$ (most stable) | | +4 | $\text{CrF}_4$ | | +5 | $\text{CrF}_5$ | | +6 | $\text{K}_2\text{Cr}_2\text{O}_7$ , $\text{CrO}_3$ |

+2 is not a common state for Cr (unstable, strong reducing agent).

Common states: +1 and +3 to +6

Answer: Option (2)

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