JEE Main · 2023 · Shift-IeasyEC-007

Which one of the following statements is correct for electrolysis of brine solution?

Electrochemistry · Class 12 · JEE Main Previous Year Question

Question

Which one of the following statements is correct for electrolysis of brine solution?

Options
  1. a

    Cl2\mathrm{Cl_2} is formed at cathode

  2. b

    O2\mathrm{O_2} is formed at cathode

  3. c

    H2\mathrm{H_2} is formed at anode

  4. d

    OH−\mathrm{OH^-} is formed at cathode

    ✓
Correct Answerd

OH−\mathrm{OH^-} is formed at cathode

Detailed Solution

Strategy: Identify the reduction half-reaction at the cathode during the electrolysis of aqueous \ceNaCl\ce{NaCl} (brine). Water is more easily redu\ced than \ceNa+\ce{Na^+}.

Step 1: Analyze cathode reaction Water undergoes reduction because its reduction potential is higher than that of sodium ions: \ce2H2O+2e−→H2(g)+2OH−(aq)\ce{2H2O + 2e^- \rightarrow H2(g) + 2OH^-(aq)} This results in the formation of Hydrogen gas and Hydroxide ions at the electrode surfa\ce.

Step 2: Verify options

  • \ceCl2\ce{Cl2} is formed at the anode.
  • \ceH2\ce{H2} is formed at the cathode.
  • \ceOH−\ce{OH^-} ions are explicitly formed in the cathode compartment.

Answer: (d) \ceOH− is formed at cathode\boxed{\text{Answer: (d) } \ce{OH^-} \text{ is formed at cathode}}

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