Match the LIST-I with LIST-II | LIST-I | LIST-II | |---|---| | A. Carbocation | I. Species that can supply a pair of…
General Organic Chemistry (GOC) · Class 11 · JEE Main Previous Year Question
Match the LIST-I with LIST-II
| LIST-I | LIST-II | |---|---| | A. Carbocation | I. Species that can supply a pair of electrons. | | B. Free radical | II. Species that can receive a pair of electrons. | | C. Nucleophile | III. hybridized carbon with empty p-orbital. | | D. Electrophile | IV. hybridized carbon with one unpaired electron. |
Choose the correct answer from the options given below:
- a
A-IV, B-II, C-III, D-I
- b
A-II, B-III, C-I, D-IV
- c
A-III, B-IV, C-II, D-I
- d✓
A-III, B-IV, C-I, D-II
A-III, B-IV, C-I, D-II
Step 1: Identify each species
(A) Carbocation: Carbon bearing a positive charge, only 3 bonds, hybridised with an empty p-orbital. → III
(B) C-Free radical: Carbon with one unpaired electron; can be or hybridised. → IV
(C) Nucleophile: Electron-rich species that donates a pair of electrons. → I
(D) Electrophile: Electron-deficient species that accepts a pair of electrons. → II
Step 2: Final match
A-III, B-IV, C-I, D-II → Option (d)
Key Points to Remember:
- Carbocation: , empty p-orbital, acts as electrophile
- Free radical: unpaired electron, neither nucleophile nor electrophile
- Nucleophile = electron donor; Electrophile = electron acceptor
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The most stable carbocation from the following is: