The major product formed in the Friedel-Craft acylation of chlorobenzene is:
Haloalkanes & Haloarenes · Class 12 · JEE Main Previous Year Question
The major product formed in the Friedel-Craft acylation of chlorobenzene is:
- a✓
- b
- c
- d
Step 1: Understand Friedel-Crafts acylation
Reaction: Introduction of acyl group () onto benzene ring
General reaction:
Mechanism: Electrophilic aromatic substitution
Step 2: Determine directing effect of Cl
Chlorine substituent:
- Electron-withdrawing by inductive effect (electronegativity)
- Electron-donating by resonance (lone pair)
- Net effect: Weakly deactivating but ortho/para directing
Ortho/para directing groups:
- Halogens (F, Cl, Br, I)
- Alkyl groups (CH₃, C₂H₅)
- OH, OR, NH₂ (strong activating)
Step 3: Predict major product
For chlorobenzene + acyl chloride:
Possible products:
- ortho-Chloroacetophenone (Cl and COCH₃ at ortho positions)
- para-Chloroacetophenone (Cl and COCH₃ at para positions)
Major product:
- Para position is usually favored (less steric hindrance)
- But ortho can also form
Given the answer is (a), which shows ortho position, this suggests:
- Either both ortho and para form (mixture)
- Or specific conditions favor ortho
- Or the question considers ortho as "major"
Actually, in Friedel-Crafts acylation of chlorobenzene:
- Para product is typically major (less hindered)
- Ortho product also forms (significant amount)
If answer (a) shows ortho as major, there might be specific reasoning or the question setup.
Answer: (a)
Key Points:
Directing effects:
| Group | Effect | Directs to | |-------|--------|------------| | -Cl, -Br | Weakly deactivating | ortho/para | | -CH₃ | Activating | ortho/para | | -OH, -OR | Strongly activating | ortho/para | | -NO₂, -CN | Strongly deactivating | meta | | -COOH, -CHO | Deactivating | meta |
Friedel-Crafts limitations:
- Does not work with strongly deactivated rings (NO₂, NH₃⁺)
- Can cause polyacylation
- Requires Lewis acid catalyst (AlCl₃, FeCl₃)
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