The major product obtained in the given reaction is:

Step 1: Identify the reaction

Ether with chloroalkyl side chain + $\ce{AlCl3}$ (Lewis acid)

This is Friedel-Crafts alkylation (intramolecular)

Step 2: Mechanism overview

$\ce{AlCl3}$ activates the C-Cl bond:

1. Activation: $\ce{R-Cl + AlCl3 -> R+ + AlCl4-}$ (carbocation formation)
2. Electrophilic attack: Carbocation attacks aromatic ring
3. Ring closure: Intramolecular cyclization

Step 3: Common mistakes to avoid

Students often:

• Forget about ring size preferences (5 and 6-membered favored)
• Don't consider intramolecular vs intermolecular
• Miss rearrangements in carbocation intermediates

Step 4: Solving strategy

For intramolecular Friedel-Crafts:

1. Identify the electrophilic center (where Cl is)
2. Determine which aromatic ring can be attacked
3. Check ring size formed (5 or 6-membered preferred)
4. Consider regiochemistry (ortho/para to activating groups)

Answer: (c)

Key Points:

Friedel-Crafts alkylation:

• Requires Lewis acid catalyst ($\ce{AlCl3}$, $\ce{FeCl3}$)
• Forms C-C bond
• Can be intramolecular (ring closure)
• Carbocation rearrangements possible

Ring size preferences:

• 5-membered (most favored)
• 6-membered (favored)
• 3, 4, 7+ membered (less favored)

Limitations:

• Doesn't work with deactivated rings (NO₂, COOH)
• Multiple alkylation can occur
• Carbocation rearrangements