JEE Main · 2020 · Shift-ImediumHC-134

Which will produce highest yield in Friedel-Crafts reaction?

Hydrocarbons · Class 11 · JEE Main Previous Year Question

Question

Which will produce highest yield in Friedel-Crafts reaction? image

Options
  1. a

    Option A

  2. b

    Option B

  3. c

    Option C

  4. d

    Option D

Correct Answerc

Option C

Detailed Solution

image Step 1: Reactivity in Friedel-Crafts Reactions Friedel-Crafts reactions require an activated ring. Deactivated rings (especially strongly deactivated) give poor or no yield.

  • (d) Aniline: lone pair on \ceNH2-\ce{NH2} reacts with the catalyst \ceAlCl3\ce{AlCl3} to form a strongly deactivating \ceNH2+AlCl3-\ce{NH2^+-AlCl3^-} complex. (Poor yield).
  • (a) Benzamide: \ceCONH2-\ce{CONH2} is deactivating.
  • (b) Phenol: lone pair on Oxygen also complexes with \ceAlCl3\ce{AlCl3}.
  • (c) Chlorobenzene: Chlorine is weakly deactivating, but it does not complex as strongly with \ceAlCl3\ce{AlCl3} compared to NN or OO lone pairs. Thus, it often gives better yields than aniline or phenol in direct FC alkylation/acylation.

From Jerry March - P709: It is important to note that the OH, OR, NH2, and so on groups do not facilitate the reaction, since most Lewis acid catalysts coordinate with these basic groups. Although phenols give the usual Friedel–Crafts reactions, orienting ortho and para, the reaction is very poor for aniline derivatives.

Answer: (c) Option C\boxed{\text{Answer: (c) Option C}}

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