JEE Main · 2024 · Shift-IeasyMOLE-160

Combustion of glucose (C6H12O6) produces CO2 and water. The amount of oxygen (in g) required for complete combustion of…

Some Basic Concepts (Mole Concept) · Class 11 · JEE Main Previous Year Question

Question

Combustion of glucose ( $\ce{C6H12O6}$ ) produces $\ce{CO2}$ and water. The amount of oxygen (in g) required for complete combustion of $900\,\text{g}$ of glucose is: [Molar mass of glucose $= 180\,\text{g/mol}$ ]

Options

a
$480$
b
$800$
c
$960$
✓
d
$32$

Correct Answerc

$960$

Detailed Solution

🧠 Glucose burns in a $1:6$ ratio with $\ce{O2}$ $\ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O}$ . So one mole of glucose needs $6$ moles of oxygen.

🗺️ Three steps Moles of glucose $= 900 / 180 = 5\,\text{mol}$ . Moles of $\ce{O2}$ needed $= 5 \times 6 = 30\,\text{mol}$ . Mass of $\ce{O2} = 30 \times 32 = 960\,\text{g}$ .

$\boxed{\text{Answer: (c)}}$

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