JEE Main · 2024 · Shift-IIeasyMOLE-159

The number of moles of methane required to produce 11\,g of CO2(g) after complete combustion is: (Molar mass of methane…

Some Basic Concepts (Mole Concept) · Class 11 · JEE Main Previous Year Question

Question

The number of moles of methane required to produce 11g11\,\text{g} of \ceCO2(g)\ce{CO2(g)} after complete combustion is: (Molar mass of methane =16g/mol= 16\,\text{g/mol})

Options
  1. a

    0.350.35

  2. b

    0.50.5

  3. c

    0.750.75

  4. d

    0.250.25

Correct Answerd

0.250.25

Detailed Solution

🧠 Methane has one carbon → 1:1 with \ceCO2\ce{CO2} Find moles of \ceCO2\ce{CO2}, that's also the moles of \ceCH4\ce{CH4} needed.

🗺️ One step Moles of \ceCO2=11/44=0.25mol\ce{CO2} = 11 / 44 = 0.25\,\text{mol}. So moles of \ceCH4\ce{CH4} needed =0.25mol= 0.25\,\text{mol}.

Speed scan 1111 is a quarter of 4444. Quarter of a mole. Done.

Answer: (d)\boxed{\text{Answer: (d)}}

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