JEE Main · 2022 · Shift-IImediumPB12-048

Among the given oxides of nitrogen; N2O, N2O3, N2O4 and N2O5, the number of compound(s) having N–N bond is

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Among the given oxides of nitrogen; N2O\mathrm{N_2O}, N2O3\mathrm{N_2O_3}, N2O4\mathrm{N_2O_4} and N2O5\mathrm{N_2O_5}, the number of compound(s) having N–N bond is

Options
  1. a

    1

  2. b

    2

  3. c

    3

    ✓
  4. d

    4

Correct Answerc

3

Detailed Solution

Strategy: Deduce the skeletal structure of different nitrogen oxides to find \ceN−N\ce{N-N} linkages.

Step 1: Structural Examination

  • \ceN2O\ce{N2O} (Nitrous oxide): Linked as \ceN≡N−O\ce{N\equiv N-O} (Contains \ceN−N\ce{N-N} bond).
  • \ceN2O3\ce{N2O3} (Dinitrogen trioxide): Existing as symmetric \ceO=N−O−N=O\ce{O=N-O-N=O} (mostly in gas) and asymmetric \ceO=N−NO2\ce{O=N-NO2} (solid/liquid). The asymmetric form contains an \ceN−N\ce{N-N} bond.
  • \ceN2O4\ce{N2O4} (Dinitrogen tetroxide): Two \ceNO2\ce{NO2} units linked as \ceO2N−NO2\ce{O2N-NO2} (Contains \ceN−N\ce{N-N} bond).
  • \ceN2O5\ce{N2O5} (Dinitrogen pentoxide): Anhydride structure with \ceO2N−O−NO2\ce{O2N-O-NO2} (No \ceN−N\ce{N-N} bond).

Step 2: Counting The oxides \ceN2O,N2O3,\ce{N2O, N2O3,} and \ceN2O4\ce{N2O4} contain \ceN−N\ce{N-N} bonds. Thus, 3 compounds fit the criteria.

Answer: (Option) [c] 3\boxed{\text{Answer: (Option) [c] 3}}

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