JEE Main · 2021 · Shift-IIeasyPB12-103

FeX2 and FeY3 are known when x and y are:

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

FeX2\mathrm{FeX_2} and FeY3\mathrm{FeY_3} are known when xx and yy are:

Options
  1. a

    x=F,Cl,Br,I\mathrm{x = F, Cl, Br, I} and y=F,Cl,Br\mathrm{y = F, Cl, Br}

    ✓
  2. b

    x=F,Cl,Br\mathrm{x = F, Cl, Br} and y=F,Cl,Br,I\mathrm{y = F, Cl, Br, I}

  3. c

    x=Cl,Br,I\mathrm{x = Cl, Br, I} and y=F,Cl,Br,I\mathrm{y = F, Cl, Br, I}

  4. d

    x=F,Cl,Br,I\mathrm{x = F, Cl, Br, I} and y=F,Cl,Br,I\mathrm{y = F, Cl, Br, I}

Correct Answera

x=F,Cl,Br,I\mathrm{x = F, Cl, Br, I} and y=F,Cl,Br\mathrm{y = F, Cl, Br}

Detailed Solution

Strategy: Apply redox chemistry to predict the stability of iron halides.

Step 1: Stability of Iron(III) Halides Iron(III) is a relatively strong oxidizing agent (E∘=+0.77 V)(E^\circ = +0.77 \text{ V}). It can oxidize iodide ions (E∘=+0.54 V)(E^\circ = +0.54 \text{ V}) to iodine. \ce2Fe3++2I−→2Fe2++I2\ce{2Fe^{3+} + 2I^- \to 2Fe^{2+} + I2} As a result, \ceFeI3\ce{FeI3} is unstable and does not exist under ordinary conditions (it reduces to \ceFeI2\ce{FeI2}).

Step 2: Comparison

  • \ceFeX2\ce{FeX2}: Stable for X = F, Cl, Br, I.
  • \ceFeY3\ce{FeY3}: Stable for Y = F, Cl, Br.

Answer: (Option) [a] \cex=F,Cl,Br,I and \cey=F,Cl,Br\boxed{\text{Answer: (Option) [a] $\ce{x = F, Cl, Br, I}$ and $\ce{y = F, Cl, Br}$}}

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