JEE Main · 2023 · Shift-IhardPB12-037

Compound A reacts with NH4Cl and forms a compound B. Compound B reacts with H2O and excess of CO2 to form compound C…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Compound A reacts with NH4Cl\mathrm{NH_4Cl} and forms a compound B. Compound B reacts with H2O\mathrm{H_2O} and excess of CO2\mathrm{CO_2} to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A, B and C, are respectively.

Options
  1. a

    CaCl2, NH3, NH4HCO3\mathrm{CaCl_2,\ NH_3,\ NH_4HCO_3}

  2. b

    CaCl2, NH4+, (NH4)2CO3\mathrm{CaCl_2,\ NH_4^+,\ (NH_4)_2CO_3}

  3. c

    Ca(OH)2, NH3, NH4HCO3\mathrm{Ca(OH)_2,\ NH_3,\ NH_4HCO_3}

  4. d

    Ca(OH)2, NH4+, (NH4)2CO3\mathrm{Ca(OH)_2,\ NH_4^+,\ (NH_4)_2CO_3}

Correct Answerc

Ca(OH)2, NH3, NH4HCO3\mathrm{Ca(OH)_2,\ NH_3,\ NH_4HCO_3}

Detailed Solution

Strategy: Correlate process names with the substances they produce.

Step 1: Process Identification

  • Deacon's Process: Production of Chlorine (\ceCl2)(\ce{Cl2}).
  • Ostwald's Process: Production of Nitric Acid (\ceHNO3)(\ce{HNO3}).
  • Contact Process: Production of Sulphuric Acid (\ceH2SO4)(\ce{H2SO4}).
  • Haber's Process: Production of Ammonia (\ceNH3)(\ce{NH3}).

Step 2: Conclusion Matching the process with the correct product provides the answer.

Answer: (Option) [c] [Correct matching set]\boxed{\text{Answer: (Option) [c] [Correct matching set]}}

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Compound A reacts with NH4Cl and forms a compound B. Compound B reacts with H2O and excess of CO2… (JEE Main 2023) | Canvas Classes