JEE Main · 2021 · Shift-ImediumPB12-068

Match List-I with List-II | | List-I (Name of oxoacid) | | List-II (Oxidation state of P) | |---|---|---|---| | (a) |…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Match List-I with List-II

| | List-I (Name of oxoacid) | | List-II (Oxidation state of P) | |---|---|---|---| | (a) | Hypophosphorous acid | (i) | +5 | | (b) | Orthophosphoric acid | (ii) | +4 | | (c) | Hypophosphoric acid | (iii) | +3 | | (d) | Orthophosphorous acid | (iv) | +2 | | - | - | (v) | +1 |

Choose the correct answer from the options given below:

Options
  1. a

    (a)-(v), (b)-(i), (c)-(ii), (d)-(iii)

  2. b

    (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

  3. c

    (a)-(iv), (b)-(v), (c)-(ii), (d)-(iii)

  4. d

    (a)-(v), (b)-(iv), (c)-(ii), (d)-(iii)

Correct Answera

(a)-(v), (b)-(i), (c)-(ii), (d)-(iii)

Detailed Solution

Strategy: Calculate the oxidation state of Phosphorus in different oxoacids.

Step 1: Oxidation State Calculation

  • Hypophosphorous acid (\ceH3PO2)(\ce{H3PO2}): 3(+1)+x+2(2)=0    x=+13(+1) + x + 2(-2) = 0 \implies x = +1.
  • Orthophosphoric acid (\ceH3PO4)(\ce{H3PO4}): 3(+1)+x+4(2)=0    x=+53(+1) + x + 4(-2) = 0 \implies x = +5.
  • Hypophosphoric acid (\ceH4P2O6)(\ce{H4P2O6}): 4(+1)+2x+6(2)=0    2x=8    x=+44(+1) + 2x + 6(-2) = 0 \implies 2x = 8 \implies x = +4.
  • Orthophosphorous acid (\ceH3PO3)(\ce{H3PO3}): 3(+1)+x+3(2)=0    x=+33(+1) + x + 3(-2) = 0 \implies x = +3.

Step 2: Matching Correct labels: (a)-v, (b)-i, (c)-ii, (d)-iii.

Answer: (Option) [a] (a)-(v), (b)-(i), (c)-(ii), (d)-(iii)\boxed{\text{Answer: (Option) [a] (a)-(v), (b)-(i), (c)-(ii), (d)-(iii)}}

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