JEE Main · 2022 · Shift-ImediumPB12-042

Match List-I with List-II, match the gas evolved during each reaction. | | List-I | | List-II | |---|---|---|---| | A |…

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Match List-I with List-II, match the gas evolved during each reaction.

| | List-I | | List-II | |---|---|---|---| | A | (NH4)2Cr2O7→Δ\mathrm{(NH_4)_2Cr_2O_7 \xrightarrow{\Delta}} | I | H2\mathrm{H_2} | | B | KMnO4+HCl→\mathrm{KMnO_4 + HCl \rightarrow} | II | N2\mathrm{N_2} | | C | Al+NaOH+H2O→\mathrm{Al + NaOH + H_2O \rightarrow} | III | O2\mathrm{O_2} | | D | NaNO3→Δ\mathrm{NaNO_3 \xrightarrow{\Delta}} | IV | Cl2\mathrm{Cl_2} |

Choose the correct answer from the options given below:

Options
  1. a

    A-II, B-III, C-I, D-IV

  2. b

    A-III, B-I, C-IV, D-II

  3. c

    A-II, B-IV, C-I, D-III

    ✓
  4. d

    A-III, B-IV, C-I, D-II

Correct Answerc

A-II, B-IV, C-I, D-III

Detailed Solution

Strategy: Determine the hybridization and lone pairs to identify the shape of the Xenon fluoride.

Step 1: Analysis For a species like \ceXeF4\ce{XeF4} (sp3d2sp^3d^2, 2 LP), the shape is Square Planar. For \ceXeF2\ce{XeF2} (sp3dsp^3d, 3 LP), the shape is Linear.

Step 2: Selection The shape identified for the specific species in the question matches the answer.

Answer: (Option) [c] [Based on shape in question]\boxed{\text{Answer: (Option) [c] [Based on shape in question]}}

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