JEE Main · 2020 · Shift-IIeasyPB12-052

Reaction of ammonia with excess Cl2 gives:

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

Reaction of ammonia with excess Cl2\mathrm{Cl_2} gives:

Options
  1. a

    NH4Cl\mathrm{NH_4Cl} and N2\mathrm{N_2}

  2. b

    NH4Cl\mathrm{NH_4Cl} and HCl

  3. c

    NCl3\mathrm{NCl_3} and NH4Cl\mathrm{NH_4Cl}

  4. d

    NCl3\mathrm{NCl_3} and HCl

Correct Answerd

NCl3\mathrm{NCl_3} and HCl

Detailed Solution

Strategy: Consider the trend in atomic size and its effect on physical properties in Group 18.

Step 1: Physical Parameters As we move down the group from \ceHe\ce{He} to \ceRn\ce{Rn}, atomic size increases and valence electrons are further from the nucleus.

Step 2: Polarizability Increased size leads to higher polarizability, which increases the strength of London dispersion forces. This manifests as higher boiling points and better solubility in water.

Answer: (Option) [d] [Based on property trend in question]\boxed{\text{Answer: (Option) [d] [Based on property trend in question]}}

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