JEE Main · 2019 · Shift-IeasyPB12-013

The correct order of the oxidation states of nitrogen in NO, N2O, NO2 and N2O3 is

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The correct order of the oxidation states of nitrogen in NO\mathrm{NO}, N2O\mathrm{N_2O}, NO2\mathrm{NO_2} and N2O3\mathrm{N_2O_3} is

Options
  1. a

    N2O<NO<N2O3<NO2\mathrm{N_2O < NO < N_2O_3 < NO_2}

    ✓
  2. b

    NO2<N2O3<NO<N2O\mathrm{NO_2 < N_2O_3 < NO < N_2O}

  3. c

    NO2<NO<N2O3<N2O\mathrm{NO_2 < NO < N_2O_3 < N_2O}

  4. d

    N2O<N2O3<NO<NO2\mathrm{N_2O < N_2O_3 < NO < NO_2}

Correct Answera

N2O<NO<N2O3<NO2\mathrm{N_2O < NO < N_2O_3 < NO_2}

Detailed Solution

Strategy: Calculate the oxidation state of Nitrogen in each given oxide.

Step 1: Calculation

  • In \ceN2O\ce{N2O} (nitrous oxide): 2x+(−2)=0  ⟹  x=+12x + (-2) = 0 \implies x = +1.
  • In \ceNO\ce{NO} (nitric oxide): x+(−2)=0  ⟹  x=+2x + (-2) = 0 \implies x = +2.
  • In \ceN2O3\ce{N2O3} (dinitrogen trioxide): 2x+3(−2)=0  ⟹  x=+32x + 3(-2) = 0 \implies x = +3.
  • In \ceNO2\ce{NO2} (nitrogen dioxide): x+2(−2)=0  ⟹  x=+4x + 2(-2) = 0 \implies x = +4.

Step 2: Final Order The correct increasing order is: \ceN2O<NO<N2O3<NO2\ce{N2O < NO < N2O3 < NO2}.

Answer: (Option) [a] \ceN2O<NO<N2O3<NO2\boxed{\text{Answer: (Option) [a] $\ce{N2O < NO < N2O3 < NO2}$}}

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