The difference in the oxidation state of Xe between the oxidised product of Xe formed on complete hydrolysis of XeF4…
p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question
The difference in the oxidation state of Xe between the oxidised product of Xe formed on complete hydrolysis of and is
- a
1
- b✓
2
- c
3
- d
4
2
Strategy: Compare the oxidation steps in Xenon fluoride hydrolysis.
Step 1: Complete Hydrolysis of XeF4 The complete hydrolysis reaction is a disproportionation: The "oxidised product" is , where Xenon is in the oxidation state.
Step 2: Difference Calculation
- Oxidation state in .
- Oxidation state in .
- Difference .
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Match List-I with List-II: | | List-I (Species) | | List-II (Number of lone pairs on central atom) | |---|---|---|---| | (a) | XeF2 | (i) | 0 | | (b) | XeO2F2 | (ii) | 1 | | (c) | XeO3F2 | (iii) | 2…
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