JEE Main · 2022 · Shift-ImediumPB12-119

The interhalogen compound formed from the reaction of bromine with excess of fluorine is a

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The interhalogen compound formed from the reaction of bromine with excess of fluorine is a

Options
  1. a

    hypohalite

  2. b

    halate

  3. c

    perhalate

  4. d

    halite

Correct Answerb

halate

Detailed Solution

Strategy: Determine the formula of the interhalogen compound formed in excess fluorine.

Step 1: Reaction Analysis Bromine reacts with an excess of Fluorine (\ceF2)(\ce{F2}) to form Bromine pentafluoride: \ceBr2+5F2(excess)2BrF5\ce{Br2 + 5F2(excess) \to 2BrF5}

Step 2: Classification In the system of oxoacids/salts:

  • +1+1: Hypohalite
  • +3+3: Halite
  • +5+5: Halate
  • +7+7: Perhalate Since Bromine in \ceBrF5\ce{BrF5} is in the +5+5 oxidation state, its corresponding oxygen-containing relatives (formed on hydrolysis, etc.) belong to the halate category.

Answer: (Option) [b] halate\boxed{\text{Answer: (Option) [b] halate}}

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