JEE Main · 2019 · Shift-ImediumPB12-090

The oxoacid of sulphur that does not contain bond between sulphur atom is:

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The oxoacid of sulphur that does not contain bond between sulphur atom is:

Options
  1. a

    H2S2O7\mathrm{H_2S_2O_7}

  2. b

    H2S2O4\mathrm{H_2S_2O_4}

  3. c

    H2S4O6\mathrm{H_2S_4O_6}

  4. d

    H2S2O3\mathrm{H_2S_2O_3}

Correct Answera

H2S2O7\mathrm{H_2S_2O_7}

Detailed Solution

Strategy: Identify the skeletal structure of given sulphur oxoacids.

Step 1: Structural Analysis

  • Pyrosulphuric acid (\ceH2S2O7)(\ce{H2S2O7}): Structure is \ceHO(O)2SOS(O)2OH\ce{HO(O)2S-O-S(O)2OH}. It contains an \ceSOS\ce{S-O-S} bridge but no direct \ceSS\ce{S-S} bond.
  • Dithionous acid (\ceH2S2O4)(\ce{H2S2O4}): Contains a direct \ceSS\ce{S-S} bond: \ceHO(O)SS(O)OH\ce{HO(O)S-S(O)OH}.
  • Tetrathionic acid (\ceH2S4O6)(\ce{H2S4O6}): Contains a linear chain of 4 sulphur atoms (\ceSSSS)(\ce{S-S-S-S}).
  • Thiosulphuric acid (\ceH2S2O3)(\ce{H2S2O3}): One sulphur atom is replaced by another in a \ceS=S\ce{S=S} double bond linkage.

Step 2: Conclusion \ceH2S2O7\ce{H2S2O7} is the acid without an \ceSS\ce{S-S} bond.

Answer: (Option) [a] \ceH2S2O7\boxed{\text{Answer: (Option) [a] $\ce{H2S2O7}$}}

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from p-Block Elements (Class 12)) inside The Crucible, our adaptive practice platform.

The oxoacid of sulphur that does not contain bond between sulphur atom is: (JEE Main 2019) | Canvas Classes