JEE Main · 2021 · Shift-ImediumPB12-118

The product obtained from the electrolytic oxidation of acidified sulphate solutions, is:

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The product obtained from the electrolytic oxidation of acidified sulphate solutions, is:

Options
  1. a

    HSO4\mathrm{HSO_4^-}

  2. b

    HO3SOOSO3H\mathrm{HO_3SOOSO_3H}

  3. c

    HO2SOSO2H\mathrm{HO_2SOSO_2H}

  4. d

    HO3SOSO3H\mathrm{HO_3SOSO_3H}

Correct Answerb

HO3SOOSO3H\mathrm{HO_3SOOSO_3H}

Detailed Solution

Strategy: Identify the major product of anodic oxidation of sulphuric acid or its salts.

Step 1: Electrochemical Reaction Electrolysis of cold, concentrated sulphuric acid or acidified sulphate solutions at high current density results in the dimerization of sulphate ions: \ce2HSO4H2S2O8+2e\ce{2HSO4^- \to H2S2O8 + 2e^-} The product is Peroxodisulphuric acid (Marshall's acid).

Step 2: Formula The chemical formula for peroxodisulphuric acid is \ceH2S2O8\ce{H2S2O8}, which can be written showing the peroxide linkage as \ce(HO)O2SOOS(O)2OH\ce{(HO)O2S-O-O-S(O)2OH} or \ceHO3SOOSO3H\ce{HO3SOOSO3H}.

Answer: (Option) [b] \ceHO3SOOSO3H\boxed{\text{Answer: (Option) [b] $\ce{HO3SOOSO3H}$}}

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