JEE Main · 2020 · Shift-IIeasyPB12-012

The reaction of NO with N2O4 at 250 K gives:

p-Block Elements (Class 12) · Class 12 · JEE Main Previous Year Question

Question

The reaction of NO with N2O4\mathrm{N_2O_4} at 250 K gives:

Options
  1. a

    N2O\mathrm{N_2O}

  2. b

    NO2\mathrm{NO_2}

  3. c

    N2O3\mathrm{N_2O_3}

  4. d

    N2O5\mathrm{N_2O_5}

Correct Answerc

N2O3\mathrm{N_2O_3}

Detailed Solution

Strategy: Identify the Nitrogen oxide produced by the direct reaction of \ceNO\ce{NO} and \ceN2O4\ce{N2O4} under cooling.

Step 1: Chemical Reaction The reaction between Nitric oxide (\ceNO)(\ce{NO}) and Nitrogen dioxide/Dinitrogen tetroxide (\ceN2O4)(\ce{N2O4}) at 250 K250 \text{ K} yields dinitrogen trioxide: \ceNO+N2O4250KN2O3\ce{NO + N2O4 \xrightarrow{250 K} N2O3}

Step 2: Key Property \ceN2O3\ce{N2O3} is observed as an intensely blue-colored solid at low temperatures. It is often referred to as nitrous anhydride since it reacts with water to form nitrous acid.

Answer: (Option) [c] \ceN2O3\boxed{\text{Answer: (Option) [c] $\ce{N2O3}$}}

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