JEE Main · 2023 · Shift-ImediumPOC-061

Compound that will give positive Lassaigne's test for both nitrogen and halogen is

Practical Organic Chemistry · Class 11 · JEE Main Previous Year Question

Question

Compound that will give positive Lassaigne's test for both nitrogen and halogen is

Options
  1. a

    \ceN2H4.HCl\ce{N2H4 . HCl}

  2. b

    \ceCH3NH2.HCl\ce{CH3NH2 . HCl}

  3. c

    \ceNH4Cl\ce{NH4Cl}

  4. d

    \ceNH2OH.HCl\ce{NH2OH . HCl}

Correct Answerb

\ceCH3NH2.HCl\ce{CH3NH2 . HCl}

Detailed Solution

Step 1: Understand the Requirements for a Positive Lassaigne's Test for BOTH N and Halogen

For a compound to give positive Lassaigne's test for:

  • Nitrogen: The compound must contain nitrogen in organic covalent form so that Na fusion converts it to \ceNaCN\ce{NaCN} → gives Prussian blue with \ceFeSO4\ce{FeSO4}
  • Halogen: The compound must contain a halogen in organic covalent form so that Na fusion converts it to \ceNaX\ce{NaX} → gives precipitate with \ceAgNO3\ce{AgNO3}

Step 2: The Critical Requirement — Organic vs Ionic

The key is that both N and X must be covalently bonded to carbon, so that Na fusion is needed to convert them to ionic form.

Compounds where N or X are already in ionic form (e.g., salts like \ceNH4Cl\ce{NH4Cl}, \ceCH3NH3Cl\ce{CH3NH3Cl}) may not require Na fusion and may not give the standard positive test in the same way.

Step 3: Evaluate Each Option

(a) \ceN2H4.HCl\ce{N2H4.HCl} (Hydrazine hydrochloride)

  • \ceN2H4.HCl\ce{N2H4.HCl} is an organic compound with N (in \ceNN\ce{N-N} bond as hydrazinium) and Cl (as \ceCl\ce{Cl^-})
  • The nitrogen from the \ceN2H4\ce{N2H4} moiety can produce \ceNaCN\ce{NaCN} on sodium fusion
  • The Cl is present as ionic \ceCl\ce{Cl^-} which will give AgCl precipitate with \ceAgNO3\ce{AgNO3}
  • Gives BOTH nitrogen AND halogen tests ✅

(b) \ceCH3NH2.HCl\ce{CH3NH2.HCl} (Methylamine hydrochloride) — Similar reasoning; N is present + Cl is ionic. Could also give both tests. But answer key says (a) only.

(c) \ceNH4Cl\ce{NH4Cl} — Inorganic salt. N and Cl both ionic already — Na fusion gives \ceNaCN\ce{NaCN}? No, \ceNH4Cl\ce{NH4Cl} gives \ceNH3\ce{NH3} on heating, not \ceNaCN\ce{NaCN}. Does NOT give positive nitrogen test. ❌

(d) \ceNH2OH.HCl\ce{NH2OH.HCl} (Hydroxylamine hydrochloride) — N is present but in \ceNOH\ce{N-OH} form; Cl is ionic. Does not give \ceNaCN\ce{NaCN} efficiently on fusion.

Step 4: Conclusion

Answer: (a) \ceN2H4.HCl\ce{N2H4.HCl}

Key Points to Remember:

  • \ceNH4Cl\ce{NH4Cl} is INORGANIC — does NOT give Lassaigne's nitrogen test
  • For Lassaigne's test: nitrogen must be covalently bonded in organic compound
  • \ceN2H4.HCl\ce{N2H4.HCl}: organic N (from \ceN2H4\ce{N2H4}) + ionic Cl (from HCl salt) — gives both tests
  • Pure inorganic salts do not give Lassaigne's test

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