JEE Main · 2023 · Shift-IImediumPOC-059

In Carius tube, an organic compound ' X ' is treated with sodium peroxide to form a mineral acid ' Y '. The solution of…

Practical Organic Chemistry · Class 11 · JEE Main Previous Year Question

Question

In Carius tube, an organic compound ' X ' is treated with sodium peroxide to form a mineral acid ' Y '. The solution of \ceBaCl2\ce{BaCl2} is added to ' Y ' to form a precipitate ' Z '. ' Z ' is used for the quantitative estimation of an extra element. ' X ' could be:

Options
  1. a

    Cytosine

  2. b

    Chloroxylenol

  3. c

    A nucleotide

  4. d

    Methionine

Correct Answerd

Methionine

Detailed Solution

Step 1: Trace the Reaction Sequence

  • Compound X is treated with sodium peroxide (\ceNa2O2\ce{Na2O2}, an oxidising agent) in a Carius tube
  • A mineral acid Y is formed
  • \ceBaCl2\ce{BaCl2} is added to Y → precipitate Z
  • Z is used for quantitative estimation of an extra element

Step 2: Identify the Precipitate Z

When \ceBaCl2\ce{BaCl2} is added to a mineral acid:

  • \ceBaCl2+H2SO4>BaSO4(v)+2HCl\ce{BaCl2 + H2SO4 -> BaSO4(v) + 2HCl} → white precipitate (BaSO₄)

So Z = \ceBaSO4\ce{BaSO4} (barium sulphate), which is used for the quantitative estimation of sulphur.

This means X contains phosphorus that gets oxidised to a phosphate acid? No — BaCl₂ + H₃PO₄ gives \ceBa3(PO4)2\ce{Ba3(PO4)2}, but that is less common in Carius method.

Actually Z = \ceBaSO4\ce{BaSO4} → mineral acid Y = \ceH2SO4\ce{H2SO4} → element estimated = Sulphur.

So X is a compound that contains sulphur (and gets oxidised to \ceH2SO4\ce{H2SO4} by \ceNa2O2\ce{Na2O2}).

But wait — it says "an extra element" — meaning an element in addition to C, H, N, O. Let me reconsider: \ceNa2O2\ce{Na2O2} oxidises phosphorus → \ceH3PO4\ce{H3PO4} (mineral acid), and \ceBaCl2+H3PO4>Ba3(PO4)2\ce{BaCl2 + H3PO4 -> Ba3(PO4)2} (precipitate). \ceBa3(PO4)2\ce{Ba3(PO4)2} is used to quantify phosphorus.

So: X contains phosphorus → oxidised to \ceH3PO4\ce{H3PO4} (acid Y) → \ceBaCl2\ce{BaCl2} added → \ceBa3(PO4)2\ce{Ba3(PO4)2} (Z) → quantify phosphorus.

Step 3: Identify Compound X

X must contain phosphorus as an "extra element" (beyond C, H, N, O):

  • (a) Cytosine: Contains C, H, N, O only — No P → ❌
  • (b) Chloroxylenol: Contains C, H, O, Cl — No P → ❌
  • (c) A nucleotide ✅ — Nucleotides contain C, H, N, O + phosphate group (P) → has the extra element phosphorus
  • (d) Methionine: Contains C, H, N, O, S (sulphur, not phosphorus) → ❌

Step 4: Conclusion

Answer: (c) A nucleotide

Key Points to Remember:

  • Nucleotides = nitrogenous base + sugar + phosphate group
  • Phosphorus in nucleotides → oxidised by \ceNa2O2\ce{Na2O2}\ceH3PO4\ce{H3PO4} → precipitated as \ceBa3(PO4)2\ce{Ba3(PO4)2} with \ceBaCl2\ce{BaCl2}
  • Carius method estimates halogens (AgX) and sulphur (BaSO₄) and phosphorus (Ba₃(PO₄)₂)
  • Methionine contains S (not P); cytosine contains no heteroatom besides N and O

Practice this question with progress tracking

Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Practical Organic Chemistry) inside The Crucible, our adaptive practice platform.