JEE Main · 2019 · Shift-IIeasyRDX-075

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one…

Redox Reactions · Class 11 · JEE Main Previous Year Question

Question

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO2\mathrm{CO_2} is:

Options
  1. a

    2

  2. b

    10

  3. c

    1

    ✓
  4. d

    5

Correct Answerc

1

Detailed Solution

Oxidation of oxalate: C2O42−→2CO2+2e−\mathrm{C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-}

C in C2O42−\mathrm{C_2O_4^{2-}}: +3+3; C in CO2\mathrm{CO_2}: +4+4

Each C loses 1e⁻ and produces one CO2\mathrm{CO_2}.

Electrons per CO2\mathrm{CO_2} = 1

Answer: Option (3) — 1

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