JEE Main · 2025 · Shift-ImediumRDX-083

Match the List-I with List-II | | List-I (Redox Reaction) | | List-II (Type) | |---|---|---|---| | A | CH4(g) + 2O2(g)…

Redox Reactions · Class 11 · JEE Main Previous Year Question

Question

Match the List-I with List-II

| | List-I (Redox Reaction) | | List-II (Type) | |---|---|---|---| | A | \ceCH4(g)+2O2(g)>CO2(g)+2H2O(l)\ce{CH4(g) + 2O2(g) -> CO2(g) + 2H2O(l)} | I | Disproportionation | | B | \ce{2Na(s) ->[\Delta] 2Na(s) + H2(g)} | II | Combination | | C | \ceV2O5(s)+5Ca(s)>2V(s)+5CaO(s)\ce{V2O5(s) + 5Ca(s) -> 2V(s) + 5CaO(s)} | III | Decomposition | | D | \ce2H2O2(aq)>2H2O(l)\ce{2H2O2(aq) -> 2H2O(l)} | IV | Displacement |

Choose the correct answer:

Options
  1. a

    A-II, B-III, C-IV, D-I

  2. b

    A-II, B-III, C-I, D-IV

  3. c

    A-III, B-IV, C-I, D-II

  4. d

    A-IV, B-I, C-II, D-III

Correct Answera

A-II, B-III, C-IV, D-I

Detailed Solution

A \ceCH4+2O2>CO2+2H2O\ce{CH4 + 2O2 -> CO2 + 2H2O}: Combustion — CH₄ combines with O₂ → Combination (II)

B \ce2NaH>2Na+H2\ce{2NaH -> 2Na + H2}: One compound breaks into simpler substances → Decomposition (III)

C \ceV2O5+5Ca>2V+5CaO\ce{V2O5 + 5Ca -> 2V + 5CaO}: Ca displaces V from its oxide → Displacement (IV)

D \ce2H2O2>2H2O+O2\ce{2H2O2 -> 2H2O + O2}: O in \ceH2O2\ce{H2O2} is -1; goes to -2 (H₂O) and 0 (O₂) — same element oxidized and reduced → Disproportionation (I)

Answer: A-II, B-III, C-IV, D-I → Option (a)

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Match the List-I with List-II | | List-I (Redox Reaction) | | List-II (Type) | |---|---|---|---| |… (JEE Main 2025) | Canvas Classes