JEE Main · 2024 · Shift-IIeasyRDX-030

Which of the following cannot function as an oxidising agent?

Redox Reactions · Class 11 · JEE Main Previous Year Question

Question

Which of the following cannot function as an oxidising agent?

Options
  1. a

    N3\mathrm{N^{3-}}

  2. b

    SO42\mathrm{SO_4^{2-}}

  3. c

    BrO3\mathrm{BrO_3^{-}}

  4. d

    MnO4\mathrm{MnO_4^{-}}

Correct Answera

N3\mathrm{N^{3-}}

Detailed Solution

Oxidising agent = species that gets reduced (gains electrons). For a species to act as an oxidising agent, the central atom must be able to decrease its oxidation state.

Step 1 — Check each species:

(1) N3\mathrm{N^{3-}}: N is in its lowest possible oxidation state (3-3). It cannot be further reduced → cannot act as oxidising agent

(2) SO42\mathrm{SO_4^{2-}}: S is +6+6, can be reduced to lower states (e.g., SO2\mathrm{SO_2}, S\mathrm{S}, H2S\mathrm{H_2S}) → can act as oxidising agent ✓

(3) BrO3\mathrm{BrO_3^{-}}: Br is +5+5, can be reduced to Br\mathrm{Br^-} (1-1) → strong oxidising agent ✓

(4) MnO4\mathrm{MnO_4^{-}}: Mn is +7+7, can be reduced to Mn2+\mathrm{Mn^{2+}}, MnO2\mathrm{MnO_2}, etc. → very strong oxidising agent ✓

Answer: Option (1) — N3\mathrm{N^{3-}}

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