JEE Main · 2021 · Shift-IIeasyRDX-002

The oxidation states of nitrogen in NO, NO2, N2O and NO3- are in the order of:

Redox Reactions · Class 11 · JEE Main Previous Year Question

Question

The oxidation states of nitrogen in $\mathrm{NO}$ , $\mathrm{NO_2}$ , $\mathrm{N_2O}$ and $\mathrm{NO_3^{-}}$ are in the order of:

Options

a
$\mathrm{NO_3^{-} > NO_2 > NO > N_2O}$
✓
b
$\mathrm{NO_2 > NO_3^{-} > NO > N_2O}$
c
$\mathrm{N_2O > NO_2 > NO > NO_3^{-}}$
d
$\mathrm{NO > NO_2 > N_2O > NO_3^{-}}$

Correct Answera

$\mathrm{NO_3^{-} > NO_2 > NO > N_2O}$

Detailed Solution

Step 1 — Calculate oxidation state of N in each compound:

| Compound | Equation | Oxidation state of N | |---|---|---| | $\mathrm{NO}$ | $x + (-2) = 0$ | $x = +2$ | | $\mathrm{NO_2}$ | $x + 2(-2) = 0$ | $x = +4$ | | $\mathrm{N_2O}$ | $2x + (-2) = 0$ | $x = +1$ | | $\mathrm{NO_3^{-}}$ | $x + 3(-2) = -1$ | $x = +5$ |

Step 2 — Arrange in decreasing order: $+5 > +4 > +2 > +1$ $\mathrm{NO_3^{-}} > \mathrm{NO_2} > \mathrm{NO} > \mathrm{N_2O}$

Answer: Option (1)

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