JEE Main · 2021 · Shift-IIeasyRDX-039

In which one of the following sets all species show disproportionation reaction?

Redox Reactions · Class 11 · JEE Main Previous Year Question

Question

In which one of the following sets all species show disproportionation reaction?

Options
  1. a

    ClO4\mathrm{ClO_4^{-}}, MnO4\mathrm{MnO_4^{-}}, ClO2\mathrm{ClO_2^{-}} and F2\mathrm{F_2}

  2. b

    MnO42\mathrm{MnO_4^{2-}}, ClO2\mathrm{ClO_2^{-}}, Cl2\mathrm{Cl_2} and Mn3+\mathrm{Mn^{3+}}

  3. c

    Cr2O72\mathrm{Cr_2O_7^{2-}}, MnO4\mathrm{MnO_4^{-}}, ClO2\mathrm{ClO_2^{-}} and Cl2\mathrm{Cl_2}

  4. d

    ClO2\mathrm{ClO_2^{-}}, F2\mathrm{F_2}, MnO4\mathrm{MnO_4^{-}} and Cr2O72\mathrm{Cr_2O_7^{2-}}

Correct Answerb

MnO42\mathrm{MnO_4^{2-}}, ClO2\mathrm{ClO_2^{-}}, Cl2\mathrm{Cl_2} and Mn3+\mathrm{Mn^{3+}}

Detailed Solution

Check each set for all species being capable of disproportionation:

Set (1): ClO4\mathrm{ClO_4^-}, MnO4\mathrm{MnO_4^-}, ClO2\mathrm{ClO_2^-}, F2\mathrm{F_2}

  • ClO4\mathrm{ClO_4^-}: Cl = +7+7 (max) → cannot disproportionate ✗
  • MnO4\mathrm{MnO_4^-}: Mn = +7+7 (max) → cannot disproportionate ✗
  • F2\mathrm{F_2}: no positive OS → cannot disproportionate ✗

Set (2): MnO42\mathrm{MnO_4^{2-}}, ClO2\mathrm{ClO_2^-}, Cl2\mathrm{Cl_2}, Mn3+\mathrm{Mn^{3+}}

  • MnO42\mathrm{MnO_4^{2-}}: Mn = +6+6 → disproportionates to MnO4\mathrm{MnO_4^-} (+7) and MnO2\mathrm{MnO_2} (+4) ✓
  • ClO2\mathrm{ClO_2^-}: Cl = +3+3 → disproportionates to Cl\mathrm{Cl^-} and ClO3\mathrm{ClO_3^-}
  • Cl2\mathrm{Cl_2}: Cl = 00 → disproportionates in alkaline medium ✓
  • Mn3+\mathrm{Mn^{3+}}: Mn = +3+3 → disproportionates to Mn2+\mathrm{Mn^{2+}} and MnO2\mathrm{MnO_2}All four can disproportionate ✓

Set (3) and (4): Contain MnO4\mathrm{MnO_4^-} (Mn = +7+7, max) or Cr2O72\mathrm{Cr_2O_7^{2-}} (Cr = +6+6, max for Cr) or F2\mathrm{F_2} → at least one cannot disproportionate ✗

Answer: Option (2)

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