1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose…
Solutions · Class 12 · JEE Main Previous Year Question
1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling points, , is: (assuming they have the same molar mass)
- a
10 : 1
- b✓
1 : 5
- c
1 : 0.2
- d
5 : 1
1 : 5
Strategy:\n> The elevation in boiling point () is proportional to the ebulliosco\pic constant () when the molality (moles of solute per kg of solvent) is constant.\n\nStep 1: Confirm same molality ()\n- Mass of solute = 1 g (for both).\n- Molar mass = same (for both).\n- Mass of solvent = 100 g (for both).\nSince all mass components are identical, both solutions have the same molality .\n\nStep 2: Relate elevation to the constants\n\nGiven the ratio of constants is , the ratio of elevations is also .\n\n
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